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forth: fix readln overflow handling
It was badly handled.
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@ -24,6 +24,9 @@
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H@ IN( !
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H@ IN( !
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INBUFSZ ALLOT
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INBUFSZ ALLOT
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H@ IN) !
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H@ IN) !
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( We need two extra bytes. 1 for the last typed 0x0a and
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one for the following NULL. )
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2 ALLOT
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(infl)
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(infl)
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;
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;
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@ -39,24 +42,22 @@
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( read one char into input buffer and returns whether we
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( read one char into input buffer and returns whether we
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should continue, that is, whether newline was not met. )
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should continue, that is, whether newline was not met. )
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: (rdlnc) ( -- f )
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: (rdlnc) ( -- f )
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( buffer overflow? stop now )
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( buffer overflow? same as if we typed a newline )
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IN> @ IN) @ = IF 0 EXIT THEN
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IN> @ IN) @ = IF 0x0a ELSE KEY THEN ( c )
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( get and echo back )
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KEY DUP ( c c )
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( del? same as backspace )
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( del? same as backspace )
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DUP 0x7f = IF DROP DROP 0x8 DUP THEN
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DUP 0x7f = IF DROP 0x8 THEN
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EMIT ( c )
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( echo back )
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DUP EMIT ( c )
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( bacspace? handle and exit )
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( bacspace? handle and exit )
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DUP 0x8 = IF (inbs) EXIT THEN
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DUP 0x8 = IF (inbs) EXIT THEN
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( write and advance )
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( write and advance )
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DUP ( keep as result ) ( c c )
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DUP ( keep as result ) ( c c )
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( Here, we take advantage of the fact that c's MSB is
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always zero and thus ! automatically null-terminates
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our string )
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IN> @ ! 1 IN> +! ( c )
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IN> @ ! 1 IN> +! ( c )
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( not newline? exit now )
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( if newline, replace with zero to indicate EOL )
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DUP 0xa = NOT IF EXIT THEN ( c )
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DUP 0xa = IF DROP 0 THEN
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( newline? make our result 0 and write it to indicate
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EOL )
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DROP 0
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DUP IN> @ ! ( c )
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;
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;
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( Read one line in input buffer and make IN> point to it )
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( Read one line in input buffer and make IN> point to it )
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@ -75,5 +76,5 @@
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( not EOL? good, inc and return )
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( not EOL? good, inc and return )
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DUP IF 1 IN> +! EXIT THEN ( c )
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DUP IF 1 IN> +! EXIT THEN ( c )
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( EOL ? readline. we still return typed char though )
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( EOL ? readline. we still return typed char though )
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(rdln) ( c )
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(rdln) (<c) ( c )
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;
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;
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