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tools: add memdumpb
In C this time. Python/Perl code is barely terser than C for these little tools. Why bother with interpreted?
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tools/.gitignore
vendored
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tools/.gitignore
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/memdumpb
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13
tools/Makefile
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tools/Makefile
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CFLAGS ?= -Wall
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MEMDUMP_TGT = memdumpb
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MEMDUMP_SRC = memdump.c
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all: ${MEMDUMP_TGT}
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${MEMDUMP_TGT}: ${MEMDUMP_SRC}
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${CC} ${CFLAGS} ${MEMDUMP_SRC} -o ${MEMDUMP_TGT}
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.PHONY: clean
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clean:
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rm -f ${MEMDUMP_TGT}
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tools/memdump.c
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tools/memdump.c
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#include <stdlib.h>
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#include <stdio.h>
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#include <fcntl.h>
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#include <unistd.h>
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/* Read specified number of bytes at specified memory address through a BASIC
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* remote shell and dump it to stdout.
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*/
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void sendcmd(int fd, char *cmd)
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{
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char junk[2];
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while (*cmd) {
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write(fd, cmd, 1);
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read(fd, &junk, 1);
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cmd++;
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// The other side is sometimes much slower than us and if we don't let
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// it breathe, it can choke.
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usleep(1000);
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}
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write(fd, "\n", 1);
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read(fd, &junk, 2); // sends back \r\n
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usleep(1000);
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}
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int main(int argc, char **argv)
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{
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if (argc != 4) {
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fprintf(stderr, "Usage: ./memdump device memptr bytecount\n");
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return 1;
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}
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unsigned int memptr = strtol(argv[2], NULL, 16);
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unsigned int bytecount = strtol(argv[3], NULL, 16);
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fprintf(stderr, "memptr: 0x%04x bytecount: 0x%04x.\n", memptr, bytecount);
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if (memptr+bytecount > 0xffff) {
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fprintf(stderr, "memptr+bytecount out of range.\n");
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return 1;
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}
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if (!bytecount) {
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// nothing to spit
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return 0;
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}
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int fd = open(argv[1], O_RDWR|O_NOCTTY);
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char s[0x20];
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sprintf(s, "m=0x%04x", memptr);
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sendcmd(fd, s);
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read(fd, s, 2); // read prompt
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for (int i=0; i<bytecount; i++) {
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sendcmd(fd, "peek m");
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read(fd, s, 2); // read prompt
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sendcmd(fd, "print a");
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for (int j=0; j<3; j++) {
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read(fd, s+j, 1);
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s[j+1] = 0; // always null-terminate
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if (s[j] < '0') {
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break;
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}
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}
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unsigned char c = strtol(s, NULL, 10);
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putchar(c);
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read(fd, s, 3); // read \r\n + prompt - last char
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sendcmd(fd, "m=m+1");
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read(fd, s, 2); // read prompt
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}
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return 0;
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}
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