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basic: add buffer line index
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12
CODE.md
12
CODE.md
@ -51,6 +51,10 @@ Therefore, shadow registers should only be used in code that doesn't call
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routines or that call a routine that explicitly states that it preserves
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shadow registers.
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Another important note is that routines returning success with Z generally don't
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preserve AF: too complicated. But otherwise, AF is often preserved. For example,
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register fiddling routines in core try to preserve AF.
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## Z for success
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The vast majority of routines use the Z flag to indicate success. When Z is set,
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@ -102,4 +106,12 @@ comments. Example:
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pop af ; <-- lvl 1
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I think that this should do the trick, so I'll do this consistently from now on.
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## String length
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Pretty much every routine expecting a string have no provision for a string
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that doesn't have null termination within 0xff bytes. Treat strings of such
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lengths with extra precaution and distrust proper handling of existing routines
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for those strings.
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[zasm]: ../apps/zasm/README.md
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@ -1,97 +1,117 @@
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; *** Consts ***
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; maximum number of lines (line number maximum, however, is always 0xffff)
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.equ BUF_MAXLINES 0x100
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; Size of the string pool
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.equ BUF_POOLSIZE 0x1000
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; *** Variables ***
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; A pointer to free space in the pool.
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.equ BUF_FREE BUF_RAMSTART
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; The line pool. Each line consists of a two bytes binary number followed by
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; a one byte length followed by the command string, which doesn't include its
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; line number (example "10 print 123" becomes "print 123"), but which is null
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; terminated. The one byte length includes null termination. For example, if
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; we have a line record starting at 0x1000 and that its length field indicates
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; 0x42, this means that the next line starts at 0x1045 (0x42+2+1).
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.equ BUF_POOL @+2
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; A pointer to the first free line
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.equ BUF_LFREE BUF_RAMSTART
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; A pointer to the first free byte in the pool
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.equ BUF_PFREE @+2
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; The line index. Each record consists of 4 bytes: 2 for line number,
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; 2 for pointer to string in pool. Kept in order of line numbers.
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.equ BUF_LINES @+2
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; The line pool. A list of null terminated strings. BUF_LINES records point
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; to those strings.
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.equ BUF_POOL @+BUF_MAXLINES*4
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.equ BUF_RAMEND @+BUF_POOLSIZE
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bufInit:
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ld hl, BUF_LINES
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ld (BUF_LFREE), hl
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ld hl, BUF_POOL
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ld (BUF_FREE), hl
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ld (BUF_PFREE), hl
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ret
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; Add line at (HL) with line number DE to the pool. The string at (HL) should
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; Add line at (HL) with line number DE to the buffer. The string at (HL) should
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; not contain the line number prefix or the whitespace between the line number
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; and the comment.
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; Note that an empty string is *not* an error. It will be saved as a line.
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; Don't send strings that are more than 0xfe in length. It won't work well.
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; Z for success.
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; The only error condition that is handled is when there is not enough space
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; left in the pool to add a string of (HL)'s size. In that case, nothing will
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; be done and Z will be unset.
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;
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; DESTROYED REGISTER: DE. Too much pushpopping around to keep it. Not worth it.
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; Error conditions are:
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; * not enough space in the pool
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; * not enough space in the line index
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bufAdd:
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push hl ; --> lvl 1
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push de ; --> lvl 2
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; First step: see if we're within the pool's bounds
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exx ; preserve HL and DE
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; First step: do we have index space?
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ld hl, (BUF_LFREE)
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ld de, BUF_POOL
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or a ; reset carry
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sbc hl, de
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exx ; restore
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; no carry? HL >= BUF_POOL, error. Z already unset
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ret nc
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; Second step: see if we're within the pool's bounds
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call strlen
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inc a ; strlen doesn't include line termination
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ld hl, (BUF_FREE)
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exx ; preserve HL and DE
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ld hl, (BUF_PFREE)
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call addHL
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; add overhead (3b)
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inc hl \ inc hl \ inc hl
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ld de, BUF_RAMEND
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sbc hl, de
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exx ; restore
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; no carry? HL >= BUF_RAMEND, error. Z already unset
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jr nc, .error
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; We have enough space, proceed
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ld hl, (BUF_FREE)
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pop de ; <-- lvl 2
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ret nc
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; We have enough space.
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; Third step: set line index data
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push de ; --> lvl 1
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push hl ; --> lvl 2
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ld hl, (BUF_LFREE)
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ld (hl), e
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inc hl
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ld (hl), d
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inc hl
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; A has been untouched since that strlen call. Let's use it as-is.
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ld (hl), a
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inc hl ; HL now points to dest for our string.
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ex de, hl
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pop hl \ push hl ; <--> lvl 1. recall orig, but also preserve
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ld de, (BUF_PFREE)
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ld (hl), e
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inc hl
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ld (hl), d
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inc hl
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ld (BUF_LFREE), hl
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pop hl \ push hl ; <-- lvl 2, restore and preserve
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; Fourth step: copy string to pool
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ld de, (BUF_PFREE)
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call strcpyM
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; Copying done. Let's update the free zone marker.
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ld (BUF_FREE), de
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xor a ; set Z
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pop hl ; <-- lvl 1
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ld (BUF_PFREE), de
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pop hl ; <-- lvl 2
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pop de ; <-- lvl 1
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ret
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.error:
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; Set IX to point to the beginning of the pool.
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; Z set if (IX) is a valid line, unset if the pool is empty.
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bufFirst:
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ld ix, BUF_LINES
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jp bufEOF
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; Given a valid line record in IX, move IX to the next line.
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; This routine doesn't check that IX is valid. Ensure IX validity before
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; calling.
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bufNext:
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inc ix \ inc ix \ inc ix \ inc ix
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jp bufEOF
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; Returns whether line index at IX is past the end of file, that is,
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; whether IX == (BUF_LFREE)
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; Z is set when not EOF, unset when EOF.
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bufEOF:
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push hl
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push de
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push ix \ pop hl
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ld de, (BUF_LFREE)
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sbc hl, de
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jr z, .empty
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cp a ; ensure Z
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.end:
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pop de
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pop hl
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ret
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.empty:
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call unsetZ
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jr .end
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; Set IX to point to the first valid line we have in the pool.
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; Error if the pool is empty.
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; Z for success.
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bufFirst:
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ld a, (BUF_POOL+2)
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or a
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jp z, unsetZ
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ld ix, BUF_POOL
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xor a ; set Z
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ret
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; Given a valid line record in IX, move IX to the next valid line.
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; This routine doesn't check that IX is valid. Ensure IX validity before
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; calling. This routine also doesn't check that the next line is within the
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; bounds of the pool because this check is done during bufAdd.
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; The only possible error is if there is no next line.
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; Z for success.
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bufNext:
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push de ; --> lvl 1
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ld d, 0
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ld e, (ix+2)
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add ix, de
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inc ix \ inc ix \ inc ix
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pop de ; <-- lvl 1
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ld a, (ix+2)
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or a
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jp z, unsetZ
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xor a ; set Z
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; Given a line index in (IX), set HL to its associated string pointer.
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bufStr:
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ld l, (ix+2)
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ld h, (ix+3)
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ret
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@ -118,8 +118,7 @@ basLIST:
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call printstr
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ld a, ' '
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call stdioPutC
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push ix \ pop hl
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inc hl \ inc hl \ inc hl
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call bufStr
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call printstr
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call printcrlf
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call bufNext
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