#include #include #include #include /* This script converts "space-dot" fonts to binary "glyph rows". One byte for * each row. In a 5x7 font, each glyph thus use 7 bytes. * Resulting bytes are aligned to the **left** of the byte. Therefore, for * a 5-bit wide char, ". . ." translates to 0b10101000 * Left-aligned bytes are easier to work with when compositing glyphs. */ int main(int argc, char **argv) { if (argc != 2) { fprintf(stderr, "Usage: ./fontcompile fpath\n"); return 1; } char *fn = basename(argv[1]); if (!fn) { return 1; } int w = 0; if ((fn[0] >= '3') && (fn[0] <= '8')) { w = fn[0] - '0'; } int h = 0; if ((fn[2] >= '3') && (fn[2] <= '8')) { h = fn[2] - '0'; } if (!w || !h || fn[1] != 'x') { fprintf(stderr, "Not a font filename: (3-8)x(3-8).txt.\n"); return 1; } fprintf(stderr, "Reading a %d x %d font\n", w, h); FILE *fp = fopen(argv[1], "r"); if (!fp) { fprintf(stderr, "Can't open %s.\n", argv[1]); return 1; } // We start the binary data with our first char, space, which is not in our // input but needs to be in our output. for (int i=0; i w+1) { // +1 because of the newline char. fprintf(stderr, "Line %d too long.\n", lineno); fclose(fp); return 1; } // line can be narrower than width. It's padded with spaces. while (l < w+1) { buf[l] = ' '; l++; } unsigned char c = 0; for (int i=0; i