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Change C<? mechanic
It's now a simple flag updated by the C< implementation. No more routine pointer. The goal is to avoid tons of "ok" during a LOAD operation.
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@ -1,5 +1,6 @@
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C<?* is a pointer to a word being called by C<?. If 0 or 1,
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will return that value as-is.
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C<? is a flag indicating whether a character is waiting in the
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input stream. 1 means yes, 0 means no. It is the responsibility
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of C<* to update that flag.
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WORDBUF is the buffer used by WORD
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@ -12,5 +13,4 @@ jump to this address. If you use one of those slots for an
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interrupt, write a jump to the appropriate offset in that RAM
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location.
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(cont.)
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2
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@ -2,7 +2,7 @@
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for an abort message )
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: (parse) (parsed) NOT IF ABORT THEN ;
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: C<? 0x06 RAM+ @ DUP 2 > IF EXECUTE THEN ( 06 == C<?* ) ;
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: C<? 0x06 RAM+ @ ;
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: C<
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0x08 RAM+ @ ( 08 == C<* override )
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DUP NOT IF DROP 0x0c RAM+ @ THEN ( 0c == C<* )
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BIN
emul/z80c.bin
BIN
emul/z80c.bin
Binary file not shown.
@ -61,17 +61,21 @@
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;
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: LOAD
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( save BLK>, C<* override and boot< ptr to RSP )
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( save restorable variables to RSP )
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BLK> @ >R
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0x08 RAM+ @ >R
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0x2e RAM+ @ >R
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0x06 RAM+ @ >R ( C<? )
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0x2e RAM+ @ >R ( boot ptr )
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BLK@
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( Point to beginning of BLK )
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BLK( 0x2e RAM+ !
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( 08 == C<* override )
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['] _ 0x08 RAM+ !
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( While we interpret, don't print "ok" after every word )
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1 0x06 RAM+ ! ( 06 == C<? )
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INTERPRET
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R> 0x2e RAM+ !
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R> 0x06 RAM+ !
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( Before we restore C<* are we restoring it to "_"?
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if yes, it means we're in a nested LOAD which means we
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should also load back the saved BLK>. Otherwise, we can
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@ -59,15 +59,18 @@
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LF IN( IN> !
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;
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: RDLN<? IN> @ C@ ;
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( And finally, implement a replacement for the (c<) routine )
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( And finally, implement C<* )
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: RDLN<
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RDLN<? ( c )
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( not EOL? good, inc and return )
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DUP IF 1 IN> +! EXIT THEN ( c )
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( EOL ? readline. we still return typed char though )
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(rdln) ( c )
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IN> @ C@
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DUP IF
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( not EOL? good, inc and return )
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1 IN> +!
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ELSE
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( EOL ? readline. we still return null though )
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(rdln)
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THEN
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( update C<? flag )
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IN> @ C@ 0 > 0x06 RAM+ ! ( 06 == C<? )
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;
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( Initializes the readln subsystem )
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@ -78,7 +81,7 @@
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the last typed 0x0a and one for the following NULL. )
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INBUFSZ 4 + ALLOT
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(infl)
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['] RDLN<? 0x06 RAM+ !
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['] RDLN< 0x0c RAM+ !
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1 0x06 RAM+ ! ( 06 == C<? )
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;
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